What is a serialVersionUID and why should I use it?
Eclipse issues warnings when a serialVersionUID
is missing.
The serializable class Foo does not declare a static final serialVersionUID field of type long
What is serialVersionUID
and why is it important? Please show an example where missing serialVersionUID
will cause a problem.
Java
- asked 9 years ago
- B Butts
2Answer
The docs for java.io.Serializable
are probably about as good an explanation as you'll get:
The serialization runtime associates with each serializable class a version number, called a serialVersionUID, which is used during deserialization to verify that the sender and receiver of a serialized object have loaded classes for that object that are compatible with respect to serialization. If the receiver has loaded a class for the object that has a different serialVersionUID than that of the corresponding sender's class, then deserialization will result in anInvalidClassException
. A serializable class can declare its own serialVersionUID explicitly by declaring a field named "serialVersionUID
" that must be static, final, and of type long
:
ANY-ACCESS-MODIFIER static final long serialVersionUID = 42L;
If a serializable class does not explicitly declare a serialVersionUID, then the serialization runtime will calculate a default serialVersionUID value for that class based on various aspects of the class, as described in the Java(TM) Object Serialization Specification. However, it is strongly recommended that all serializable classes explicitly declare serialVersionUID values, since the default serialVersionUID computation is highly sensitive to class details that may vary depending on compiler implementations, and can thus result in unexpected InvalidClassExceptions
during deserialization. Therefore, to guarantee a consistent serialVersionUID value across different java compiler implementations, a serializable class must declare an explicit serialVersionUID value. It is also strongly advised that explicit serialVersionUID declarations use the private modifier where possible, since such declarations apply only to the immediately declaring class--serialVersionUID fields are not useful as inherited members.
- answered 8 years ago
- Sunny Solu
I can't pass up this opportunity to plug Josh Bloch's book Effective Java (2nd Edition). Chapter 11 is an indispensible resource on Java serialization.
Per Josh, the automatically-generated UID is generated based on a class name, implemented interfaces, and all public and protected members. Changing any of these in any way will change the serialVersionUID
. So you don't need to mess with them only if you are certain that no more than one version of the class will ever be serialized (either across processes or retrieved from storage at a later time).
If you ignore them for now, and find later that you need to change the class in some way but maintain compatibility w/ old version of the class, you can use the JDK tool serialver to generate the serialVersionUID
on the old class, and explicitly set that on the new class. (Depending on your changes you may need to also implement custom serialization by adding writeObject
and readObject
methods - see Serializable
javadoc or aforementioned chapter 11.)
- answered 8 years ago
- G John
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